Question

DATA: Data Table 1: NaHCO, Reaction Data Mass of evaporating dish (g) Mass of evaporating dish + NaHCO, (g) Mass of NaHCO; (g) Mass of evaporating dish + NaCl product after 1" heating (8) Mass of evaporating dish + NaCl product after 2" heating (g) Mass of evaporating dish + NaCl product after 30 heating (g) (if necessary) Mass of NaCl product (g) (actual yield) 47,303 47.6917 13214 3 47.6213 47.59425 47.5938

calculate the mass of NaCl from the data table (first photo). Then perform 1b and question 2.

Just FYI. This data is lab is two parts with diffrent numbers but same question. If I can figure out this portion that im asking, I’ll be able to do the rest.

Answer 1

Question 1.

a) Moles of NaHCO3 = 0.3214 g/(84 g/mol) = 0.003826 mol

Moles of NaCl = 0.2908 g/(58.5 g/mol) = 0.004971 mol

b) The mole-to-mole ratio of NaHCO3:NaCl = 0.003826/0.003826 : 0.0049710.003826 = 1:1.299 (before rounding)

The mole-to-mole ratio of NaHCO3:NaCl = 1:1.3 (after rounding)

The expected mole-to-mole ratio of NaHCO3:NaCl = 1:1

Question 2.

The limiting reactant is NaHCO3.

The theoretical yield of product = 0.003826 mol * 58.5 g/mol = 0.2238 g

The percent yield of product = (0.2908/0.2238)*100 = 129.94%