Question

can you respond to the 3 questions in the second photo

Mole Ratios and Reaction Stoichiometry Reaction A: Sodium Bicarbonate and Hydrochloric Acid Experimental Data (a) Mass of evaporating dish + watch glass (6) Mass of evaporating dish + watch glass + sodium bicarbonate (c) Mass of sodium bicarbonate used (d) Mass of evaporating dish + watch glass + sodium chloride (e) Mass of sodium chloride collected (experimental yield) 164.79 165.19 10. 49 165.19 164.7 9 Data Analysis 1) Use your data to determine the experimental mole-to-mole ratio between sodium bicarbonate and sodium chloride. Show your work for each step. Mass of suchun bicarbonate 0.4% Convert the mass of sodium bicarbonate used to moles. A 1 0 .49 -0.00476 md (NaHCO3) = 84 g mot 84 MO1 9,-,-0.00644 Moloss 0.49 58.4499 Miles of Natcom = 0.00476 md=4.76x103 mole • Convert the mass of sodium chloride collected to moles. Nac=164.79 = 164.79 Molar Mass = mass of Nac! . molar mass of each 58.14 g mol = 2,818 mol Mass of Nad: 58.44g mol-1 Divide both of your results from the preceding two steps by the lower mole value to determine the simplest mole-to-mole ratio between sodium bicarbonate and sodium chloride. Smallest no. Of moes: 0.00H 76 mol NaHCO3 = 0,00476 mol = 1 nacl = 2.818 mol = 592 0.00476 mot 0.00476 wol Simplest mole ratio before rounding A moles moles NaHCO; : 6544 moles Naci Simplest whole number mole ratio after rounding mole moles NaHCO; : I mole moles Naci jach-0.00654 0.004076 1.44 Page 1 of 3

Answer 1

* Balanced chemical equation for reaction A. NaHCO3 + HCl - NaCl + H₂O + CO2 According to Balanced chemical equation, Mofar mass of NaHCO3 = 849mol Molar mass of NaCl = 58.44g mol Molar mass of HCl = 36-45gmol Molar mass of H2O = 18gmol Molar mass of Con = 449 mol Since we are discussing about the major product Nach, • According to balanced equation 849 of Nah log reacts with 36.459 of HCl to form 58.449 of Nach Mass of sodium bicarbonate = 0.49 58.44g of Nach is formed from 84g of NaHCO₃. .. mass of Naci formed from 0.49 of NaH003 = 0.49 of NaHCO3 x 58.449 of Naci 849 of NCHCO3 = 0.2189 Nach The theoretical yield of NACI= 0-2789 * Percent yield - Actual yield Theoretical yield = 0.49 x 100. 0.278 '143.88% Percent yield. = * Percent yield greater than 100 indicates the presence of impurities in the sample collected (NaCl).