Question

side up on top of the disn, but ipped sngitlyc Tm prop back into the evaporating dish. up will allow condensation to drain Ge

3. Calculate the mass of the product, NaCl. 4. Calculate the moles of NaCl produced. Calculate the experimental mole ratio of

side up on top of the disn, but ipped sngitlyc Tm prop back into the evaporating dish. up will allow condensation to drain Ge

Thank you.

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Answer #1

Solution-

1) Calculate mass of reactant NaHCO3

Mass of dish , glass and NaHCO3 - mass of dish and glass

=95.35-92.83

=2.52 g of NaHCO3

2) Number of moles of NaHCO3=?

We know molar mass of NaHCO3= 84.0066g/mol

Mass of NaHCO3= 2.52g

We can use formula-

Moles of NaHCO3= mass of NaHCO3/ molar mass of NaHCO3

= 2.52/ 84.0066

=0.02999 moles of NaHCO3

3)mass of product Nacl=?

Mass of dish ,glass and residue (NaCl) after second heating- mass of dish and glass

= 94.52-92.83

= 1.69 g of NaCl

4) mole of NaCl produced =?

Mass of NaCl= 1.69 g

Molar mass of NaCl=58.44g /mol

So moles of NaCl= mass of NaCl/ molar mass of NaCl

= 1.69/58.44

= 0.02891 moles of NaCl

5) Experimental mole ratio of NaCl/ NaHCO3=?

Moles of NaHCO3= 0.02999 moles

Moles of NaCl= 0.02891 moles

Molar ratio of NaCl to NaHCO3= 0.02891/0.02999

= 0.96

6) Balances reaction -

NaHCO3 + HCl = NaCl + H2O + CO2

7) by observing balance reaction it is clear that one mole of NaHCO3 would produced one mole of NaCl, so its molar ratio should be 1 theoretically.

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