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The control of the spark iginition of an automobile engine requires constant performance over a wide range of parameters. The

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Answer #1

*30m TF characteristic equation s, 533+ $[ 25+k+5p) + sf 25p + kp+24] +5 k = 0 By using Routh Hurwitz (R-H) Criteria Casei P55° + s[25+k] + sf 2x]+56=0 535 2k 2K Rough 25+k 5k (25+k) (2K) - 25k 25+k RC 2k-25) 50k + 2 kr - 25k 25+k 25+k 2k - 25k 25please take answer in this order.

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​​​Bч uѕіm) isting Block 6 Diagram Reduction Techniques, 5 i+55 RO) →Y) (s+p)(5(5+5)*2) RUS) ) (S+P)[5(5+5)+k]+k yes) 2. Transfe

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