We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
6. a. What is the pH of a 0.085 mol/L solution of benzoic acid, C.HSCOOH? K,...
What is the pH of 0.7 mol/L benzoic acid solution? benzoic acid = (C6H5COOH, Ka = 6.6 x 10-5) A. 2.17 B. 11.8 C. 4.34 D. 9.80
Calculate the pH of a solution prepared by dissolving 0.050 mol of benzoic acid (HA) and 0.50 mol of sodium benzoate (A-) in water sufficient to yield 1.00 L of solution. The Ka of benzoic acid is 6.30 x 10-5 A. 5.20 B. 1.30 C. 7.00 D. 3.20 E. 4.20
1) What is the pH of a 0.085 M solution of acetic acid, HC2H3O2? At 25 degrees C, the Ka of acetic acid is 1.8 x 10^-5. 2) 17.4 mL of 4.0 M HCl are diluted with water to make 1.5 L of solution. What should be the pH of the final solution?
Consider a weak acid "HA". What is the pH of a 0.853 mol L-1 solution of HA? The KA of HA is 6.32 x 10-6
What is the pH of a 1 L solution containing 0.5 mol of propionic acid and 0.4 mol of sodium propionate? Ka for propionic acid = 1.3 x 10-5. Select one: O a. 4.8 O b. -1.3 C. 1.3 O d. -5.0 e. 5.0 O O O
Consider a weak acid "HA". What is the pH of a 1.055 mol L-1 solution of HA? The KA of HA is 1.73 x 10-7 . You have 5 attempts at this question. Remember: if you want to express an answer in scientific notation, use the letter "E". For example "4.32 x 104" should be entered as "4.32E4".
Calculate the pH of a 0.500 L solution of 0.800 mol NaCH3CO2. Ka for acetic acid, CH3CO2H, is 1.8 x 10:5. 2.27 9.47 ooo 11.73 4.53
What is the pH of a solution made by adding 0.30 mol of acetic acid (Ka = 1.8 x 10-5) to enough water to make 1.0 L of solution?
i need help with 6 b) please 6. a) Calculate the pH of a solution prepared by dissolving 0.0775 mol acetic acid and 0.0460 mol sodium acetate in 1 L of water. (Ka = 1.8 x 10-5) ANSWER: 4.52 b) Calculate the pH of the above solution if 0.0100 mol of KOH is added to this solution. ANSWER: 4.66
What is the pH of a solution containing 0.342 mol L-1 NH3 and 0.140 mol L-1NH4? Round your answer to 2 decimal places. Remember you can find KA and/or Kg values in your textbook in chapter 15. Answer: Check A 45.3 mL solution of 0.283 mol L-1 HCl is titrated using 0.820 mol L-'NaOH. What volume of NaOH (in mL) is needed to reach the equivalence point in this experiment? Remember you can find KA and/or Ke values in your...