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(a) How much heat transfer (in kJ) is necessary to raise the temperature of a 0.210 kg piece of ice from -22.0°C to 132°C, in

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Solution: - a) DH heat requured te for temproture change from (-22°C to o°c) = mgat - 0.210 X 2.108X(D-(-22) AH, = 9.74 kj DHb) t = DHI 9.74 19 To- 0.51sec DH2 19 40.32 19 2.12 sec DH3 19 50.23 19 - 2.64 sec. t2 = 962 - 10:32 = 2.12 sec to - moto - 5

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