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If F, = 200 N. F2 = 400 N and F3 = 350 N. determin
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The position vector is, F-200 N. F-400 N. F -350 N For equilibrium, total force at point o should be zero 20N F 400x F (-114.

The direction of this force is, (214.28 +121.42-)-642.84k) 1214.28)·4(121.42). (642.84) T-0.31i +0.17j-0.93k

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