can you identify some rules of how R is calculated for a circuit in series? For a circuit in parallel?
Solution :
1. The resistance in series gets add up, due to which the net resistance is always greater than individual resistance.
So net resistance
R = R1 + R2 + R3 + ...........Rn
Ex: the net resistance of series combination of 2, 3 , 4 ohm is (2+3+4) = 9 ohms.
2. In parallel the inverse of net resistance is equal to the sum of inverse of individual resistance.
So 1/R = (1/R1 + 1/R2 + 1/R3.......1/Rn)
Ex.: The parallel resistance of the above problem will be
1/R = 1/2 + 1/ 3 + 1/ 4 taking LCM and solving it
That is 1/R = ( 6+4+3)/12 = 13/12
So R = 12/13.
This is less than individual resistance.
can you identify some rules of how R is calculated for a circuit in series? For...
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