Question

program that does the following exactly once: int W e a complete C program that does the • Uses a user validation loop to prompt its u that they have eaten in the last (30 days) (0; 250 ) • Computes and prints (to the screen th (which may have a fractional component). Hlut • Displays exactly one of the following - if the average number of pompt its user to enter the non-negative number of hamburgers ist (30 days) month, and stores the response into a variable of type while o the screen the average number of hamburgers that were eaten per day le of the following messages (based on the given criteria): e average number of hamburgers eaten per day is greater than 0.5, print (to the screen) the message: "That is a lot of burgers if the average number of hamburgers eaten per day is equal mber of hamburgers eaten per day is equal to 0. print (to the screen) the message: "I do not believe you" - if the average number of ha average number of hamburgers eaten per day is greater than 0 but less than or equal 1.0, Print (to the screen) the message: "That sounds reasonable" Sample run(s): run 1 ----------- Enter number of hamburgers eaten in (30 days) : -10 Enter number of hamburgers eaten in (30 days) : -2 Enter number of hamburgers eaten in (30 days) : 18 The average number of hamburgers eaten per day was 0.6 That is a lot of burgers run 1 run 2 ----- Enter number of hamburgers eaten in (30 days) : 0 The average number of hamburgers eaten per day was 0.0 I do not believe you run 2 ------- run 3 ---- Enter number of hamburgers eaten in (30 days) : 12 The average number of hamburgers eaten per day was 0.4 That sounds reasonable run 3 -

Answer 1

C-Code

Explaination  

Note (point 1 and 3 are important )

1. Main point where you might get stuck is how to ensure that user is entering a non-negative number so i uses a while loop which run until until user is entering a negative number .

2. Calculate avg i.e n/30;

3. Now one point ot look into here question says to take input into a variable of int type and avg we want in point so we will take it float but here when we do divide n/30 so to get ans is float we need to type case n into float for getting proper results

so i did float avg=(float)n/30;

4. Then simply apply if - else and write required printf statements

Code is

 #include<stdio.h> int main() { int n; printf("Enter number of hamburgers eaten in (30 days) :" ); scanf("%d",&n); while(n<0)// will run until user enters a non-negative number { printf("Enter number of hamburgers eaten in (30 days) :" ); scanf("%d",&n); } float avg; avg= (float)n/30; // type casting n to get float ans for avg printf("\nThe number of hamburgers eaten per day was %.1f \n",avg); if(avg >0.5) { printf("That is a lot of burgers \n"); } else if(avg==0.0) { printf("I don't believe you \n"); } else { printf("That's sound reasonable \n"); } } 

Input

Output for run 1

#include<stdio.h> int main() int n; printf ("Enter number of hamburgers eaten in (30 days) :" ); scanf("%d", &n); while (no) printf("Enter number of hamburgers eaten in (30 days) :" ); scanf("%d",&n); float avg; avg= (float) n/30; printf("\nThe number of hamburgers eaten per day was $.1f \n", avg); if(avg >0.5) printf ("That is a lot of burgers \n"); else if(avg==0.0) printf("I don't believe you \n"); else printf ("That's sound reasonable \n"); Blocks X Search results x Coccx Build log x Build messages x CppCheck/Vera++ x CppCheck/Vera++ messages X Cscope x Debugger x DoxyBlocks x Fortran info Line Message === Build file: "no target" in "no project" (compiler: unknown) === === Build finished: 0 error(s), 0 warning(s) (0 minute(s), 0 second(s)) ===

- O X "C:\Users\Sudhanshu Goel\Desktop\ces3 c programing\hamburgers.exe" Enter number of hamburgers eaten in (30 days) :-10 Enter number of hamburgers eaten in (30 days) :-2, Enter number of hamburgers eaten in (30 days) :18 The number of hamburgers eaten per day was 0.6 That is a lot of burgers execution time : 9.728 s Process returned 0 (0x0) Press any key to continue.

Output for Run 2

- 0 x "C:\Users\Sudhanshu Goel\Desktop\ces3 c programing\hamburgers.exe" Enter number of hamburgers eaten in (30 days) :0 The number of hamburgers eaten per day was 0.0 I don't believe you Process returned 0 (0x0) execution time : 1.925 s Press any key to continue.

Output for Run 3

- O X "C:\Users\Sudhanshu Goel\Desktop\ces3 c programing\hamburgers.exe" Enter number of hamburgers eaten in (30 days) :12 The number of hamburgers eaten per day was 0.4, That's sound reasonable execution time : 1.802 s Process returned o (0x0) Press any key to continue.

Thank You

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