Question

The floor beams AB and BC are stiffened using the two tie rods CD and AD. Determine the force along each rod. Assume the three contacting members at B ate smooth and the joints at A, C, and D are pins.

960 lb 960 lb 6 ft 6 ft А S ft - 12 ft 12 ft

Answer Choices

a) T=1248 lb

b) T=480 lb

c) T=1152 lb

d) T= 520 lb

Answer 1

Solution- Free body diagrams for Beams AB & BC:- 960lb 1960.16 FK PBC FAB Apply Equilibrium Egn's :- Os Imao > FARX12=960x6 → Frie=4801b Because of Symmetry FAB FAC = 480 lb Now free body diagram for rods ADC is ir TAP FAB FBC stoc Toc 54 A Here os teñ' ( ) = 22.62 Apply Equilibrium Eqn's : {&q=0) TAD Coso = Tocoso {fy 20 = & FAB = TAD Sino + TocSino [:: FAB=FBC & Rica] Tan Toc T] = 24.480= Termott Gino --> 2x480 = 2TSimo =) Tz 480 = 1248 lb San(22.62) . T = 124816 Answer