Question

Use the Relerences to access important values if needed for this question. A buffer solution that is 0.475 M in CH, COOH and
part 1 dropdown box:
-increase slightly
-increase by 2 units
-decrease slightly
-decrease by 2 units
-not change

part 2 dropdown
-of the weak acid
-of the salt
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Answer #1

1)

Answer : decrease slightly

moles of CH3COOH = 0.475

moles of CH3COOK = 0.475

moles of H+ = 0.01

pH = pKa + log [salt - C / acid + C]

    = 4.74 + log [0.475 - 0.01 / 0.475 + 0.01]

pH = 4.72

2)

Answer : of the salt

moles of NaOH =

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