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can you solve the last (29)
question and first 3 (22, 23, 24) questions.
VI 16920...
A light bulb manufacturer guarantees that the mean life of a certain type of light bulb...
A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 743 hours. A random sample of 21 light bulbs has a mean life of 717 hours. Assume the population is normally distributed and the population standard deviation is 64 hours. At a = 0.05, do you have enough evidence to reject the manufacturer's claim? Complete parts (a) through (e) (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: $717...
A sample of 35 observations is selected from a normal population. The sample mean is 16,...
A sample of 35 observations is selected from a normal population. The sample mean is 16, and the population standard deviation is 4. Conduct the following test of hypothesis using the 0.05 significance level. Họ: H = 15 Hi: 4 > 15 a. Is this a one-or two-tailed test? One-tailed test Two-tailed test b. What is the decision rule? Reject Ho when z> 1.645 Reject Ho when zs 1.645 c. What is the value of the test statistic? (Round your...
I will be sure to rate well, Thanks! The quality-control manager at a compact fluorescent light...
I will be sure to rate well, Thanks!
The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a large shipment of CFLs is equal to 7,498 hours. The population standard deviation is 700 hours. A random sample of 49 light bulbs indicates a sample mean life of 7,348 hours. a. At the 0.05 level of significance, is there evidence that the mean life is different from 7,498 hourst b. Compute...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. (a) Suppose that the standard deviation of the differences...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. USE SALT (a) Suppose that the standard deviation of...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. in USE SALT (a) Suppose that the standard deviation...
Question 1 4.5 pts Given are five observations for two variables, x and y. 3 2...
Question 1 4.5 pts Given are five observations for two variables, x and y. 3 2 7 h. Compute the mean square error (MSE) O 3.875 4.133 4.421 4.312 i. Compute the standard error of the estimate 2.326 1.895 2.033 2.213 j. Compute the estimated standard deviation (standard error) of bu 0.643 0.697 0.568 O 0.713 k. Test for a significant relationship using the t test. Compute the value of the test statistic and the p-value. At a = 0.05,...
Problem #3 You have five samples of interior room temperatures as follows: 23.01, 22.22, 22.04, 22.62,...
Problem #3 You have five samples of interior room temperatures as follows: 23.01, 22.22, 22.04, 22.62, and 22.59. You want to test the hypotheses Ho: μ-22.5 versus HI: μ 22.5 using an α =0.05 一-22.4% σ 0.378 (a) Compute the appropriate statistic (b) Compute the P-value for this problem (c) Do you recommend to accept or reject the null hypothesis a. Yes - reject null hypothesis b. No - fail to reject the null hypothesis (d) Compute the Lower bound...
The lumen output was determined for each of I = 3 different brands of lightbulbs having...
The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with ) = 7 bulbs of each brand tested. The sums of squares were computed as SST = 593.9 and SSE = 4777.5. State the hypotheses of interest (including word definitions of parameters). uj = true average lumen output for brand i bulbs Ho: ui = u2 = 43 Ha: at least two ui's are unequal uj = true average lumen...
The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the...
The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a large shipment of CFLs is equal to 7,520 hours. The population standard deviation is 840 hours. A random sample of 49 light bulbs indicates a sample mean life of 7,340 hours. a. At the 0.05 level of significance, is there evidence that the mean life is different from 7,520 hours? b. Compute the p-value and interpret its meaning. c. Construct...
A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 743 hours. A random sample of 21 light bulbs has a mean life of 717 hours. Assume the population is normally distributed and the population standard deviation is 64 hours. At a = 0.05, do you have enough evidence to reject the manufacturer's claim? Complete parts (a) through (e) (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: $717...
A sample of 35 observations is selected from a normal population. The sample mean is 16, and the population standard deviation is 4. Conduct the following test of hypothesis using the 0.05 significance level. Họ: H = 15 Hi: 4 > 15 a. Is this a one-or two-tailed test? One-tailed test Two-tailed test b. What is the decision rule? Reject Ho when z> 1.645 Reject Ho when zs 1.645 c. What is the value of the test statistic? (Round your...
I will be sure to rate well, Thanks!
The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a large shipment of CFLs is equal to 7,498 hours. The population standard deviation is 700 hours. A random sample of 49 light bulbs indicates a sample mean life of 7,348 hours. a. At the 0.05 level of significance, is there evidence that the mean life is different from 7,498 hourst b. Compute...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. (a) Suppose that the standard deviation of the differences...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. USE SALT (a) Suppose that the standard deviation of...
Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse designs. The difference in wrist extension was calculated by subtracting extension for mouse type B from the wrist extension for mouse type A for each person. The mean difference was reported to be 8.82 degrees. Assume that this sample of 24 people is representative of the population of computer users. in USE SALT (a) Suppose that the standard deviation...
Question 1 4.5 pts Given are five observations for two variables, x and y. 3 2 7 h. Compute the mean square error (MSE) O 3.875 4.133 4.421 4.312 i. Compute the standard error of the estimate 2.326 1.895 2.033 2.213 j. Compute the estimated standard deviation (standard error) of bu 0.643 0.697 0.568 O 0.713 k. Test for a significant relationship using the t test. Compute the value of the test statistic and the p-value. At a = 0.05,...
Problem #3 You have five samples of interior room temperatures as follows: 23.01, 22.22, 22.04, 22.62, and 22.59. You want to test the hypotheses Ho: μ-22.5 versus HI: μ 22.5 using an α =0.05 一-22.4% σ 0.378 (a) Compute the appropriate statistic (b) Compute the P-value for this problem (c) Do you recommend to accept or reject the null hypothesis a. Yes - reject null hypothesis b. No - fail to reject the null hypothesis (d) Compute the Lower bound...
The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with ) = 7 bulbs of each brand tested. The sums of squares were computed as SST = 593.9 and SSE = 4777.5. State the hypotheses of interest (including word definitions of parameters). uj = true average lumen output for brand i bulbs Ho: ui = u2 = 43 Ha: at least two ui's are unequal uj = true average lumen...
The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a large shipment of CFLs is equal to 7,520 hours. The population standard deviation is 840 hours. A random sample of 49 light bulbs indicates a sample mean life of 7,340 hours. a. At the 0.05 level of significance, is there evidence that the mean life is different from 7,520 hours? b. Compute the p-value and interpret its meaning. c. Construct...
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month
total distribution cost
level of activity (unit produced)
july
230.000
3500
august
250.000
3750
september...
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