The puck in the figure has a mass of 0.17 kg. Its original distance from the center of rota- tion is 41.2 cm, and the puck is moving with a speed of 67.5 cm/s. The string is pulled downward 11.8 cm through the hole in the frictionless table.
What is the magnitude of the work was done on the puck? Treat the hockey puck as a point mass. Answer in units of J.
Given mass of puck is m = 0.17 kg
r1 = 41.2 cm = 0.412 m, v1 = 67.5 cm/s = 0.675 m/s
r2 = 41.2-11.8 cm = 29.4 cm = 0.29 m
we know that angular momentum is constant
by conservation of angular momentum
L1 = L2
m v1r1 = m v2r2
V2 = v1r1/r2
= 0.675*0.412/0.29
= 0.959 m/s
now change in k.e = 0.5*m(v2^2 - v1^2)
= 0.5*0.17(0.959^2 -0.675^2) J
which is equal to work done on puck to pull it to a distance of 11.8 cm down
from work energy theorem , work done = change in k.e
The puck in the figure has a mass of 0.17 kg. Its original distance from the...
The puck in the figure below has a mass of 0.160 kg. Its original distance from the center of rotation is 40.0 cm, and it moves with a speed of 85.0 cm/s. The string is pulled downward 15.0 cm through the hole in the frictionless table. Determine the work done on the puck. Hint: Consider the change in kinetic energy of the puck.
The puck in the figure below has a mass of 0.140 kg. Its
original distance from the center of rotation is 40.0 cm, and it
moves with a speed of 85.0 cm/s. The string is pulled downward 15.0
cm through the hole in the frictionless table. Determine the work
done on the puck. (Hint: Consider the change of kinetic
energy of the puck.)
______J
Please help.
And please respond and try again if the answer is wrong
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