The puck in the figure below has a mass of 0.140 kg. Its original distance from...
The puck in the figure below has a mass of 0.140 kg. Its original distance from the center of rotation is 40.0 cm, and it moves with a speed of 85.0 cm/s. The string is pulled downward 15.0 cm through the hole in the frictionless table. Determine the work done on the puck. (Hint: Consider the change of kinetic energy of the puck.)
______J
Homework Answers
intial ke = 1/2*.14*.85^2 = 0.050575
final KE = 1/2*.14*(.85*15/40)^2 = 0.00711
work done = 0.0435J
T=m*v^2/r =0.14*0.85^2/0.4=0.252875
now 0.252875=0.14*v^2/0.25
V^2=0.4515625
v=0.6719m/s
work done = change in kinetic energy=0.5*0.14*(0.85^2-0.6719^2)=0.01897J
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The puck in the figure below has a mass of 0.140 kg. Its
original distance from...
The puck in the figure below has a mass of 0.160 kg. Its original distance from...
The puck in the figure below has a mass of 0.160 kg. Its original distance from the center of rotation is 40.0 cm, and it moves with a speed of 85.0 cm/s. The string is pulled downward 15.0 cm through the hole in the frictionless table. Determine the work done on the puck. Hint: Consider the change in kinetic energy of the puck.
The puck in the figure has a mass of 0.17 kg. Its original distance from the...
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What is the magnitude of the work was done on the puck? Treat
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Please help. And please respond and try again if the answer is wrong 12. [lpt] The...
Please help.
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Please help.
And please respond and try again if the answer is wrong
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