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Fapplied 12°
(8) 2. Two blocks of mass m = 2.0 kg and m2 = 3.6 kg are tied together by a string. A force of 25 N is applied at 8 = 12° abo
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F=250 ca 12:0 m₂ tt Im ga 3-69 b) T-ag=2a-B Horizontally F loso-T= m, a 2568 12°-T= 3.62 - 0 ® + Ⓡ 256312-29 - 5.60 Ja=0.867

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