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Find the z value to the right of the mean so that a. 54.78% of the area under the distribution curve lies to the left of it. please show work and explain.
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Answer #1

a)

P(x < a) = 0.5478

Z score at p = 0.5478 using excel = NORM.S.INV(0.5478) = 0.1201

Area = 0.5478 3 2 -1 i

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b)

P(x < a) = 0.6985

Z score at p = 0.6985 using excel = NORM.S.INV(0.6985) = 0.5201

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c)

P(x < a) = 0.881

Z score at p = 0.881 using excel = NORM.S.INV(0.881) = 1.1800

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