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3. How many moles of HCl are there in 0.1 L of 0.1 M HCI? 4. In Lab 5, you will be using a compound ONPG which has a molecula
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Answer #1

3) Moles of HCl = molarity×volume (in L)

= 0.01 moles

4) Molar concentration (M) = mass/molar mass×volume(L)

= 30/300×1

= 0.1 M

Concentration in mM = 0.1×1000 = 100 mM

5) mass = molarity×volume×molar mass

= 0.333×1×300 g

= 99.9 g

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