At 250C the vapor pressure of mercury is 74.4 torr and at 320C
the vapor pressure is 376.3 torr. Find the
Hvap in KJ/mol.
T1 = 25.0 oC
=(25.0 + 273)K
= 298.0 K
T2 = 32.0 oC
=(32.0 + 273)K
= 305.0 K
P1 = 74.4 torr
P2 = 3.763*10^2 torr
use:
ln(P2/P1) = (Hvap/R)*(1/T1 - 1/T2)
ln(3.763*10^2/74.4) = ( Hvap/8.314)*(1/298.0 - 1/305.0)
1.620931 = (Hvap/8.314)*(7.702*10^-5)
Hvap = 174982 J/mol
Hvap = 175 KJ/mol
Answer: 175 KJ/mol
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