Question

1. Find 7(5) 3 5n+12n+1 sin(n!) lim (a) im (b) n 2018 пH0 п2 n oo _ Зп? + п + 4(3) nt T lim sin (d) (с) lim 1 - 2n 3п — 2п

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Answer #1

Jim im 8 = - h1 +2ht) 1+ 5 hooo is ss thn Bath quandidy end h tonds ta Aads Cis CAnd Sih h Sin(h) R018 n2 hoo h2 tnds to and(Dd) Sin S 2h S- -2 and n cantinwcous fune ticsn Sin mds ta hlimty tnds ta us 2 an) bu Ssqusncs CAn L me lN s-t en-L thun htL

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1. Find 7(5") 3" 5n+12n+1 sin(n!) lim (a) im (b) n 2018 пH0 п2 n oo...
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