Question

The rigid beam BD is supported by a smooth pin B, two circular rods at points C and D and is subjected to two concentrated loads as illustrated below. Neglect the weight of the rigid beam and assume that when W= 0 the rigid beam is in the horizontal position and the rods are stress-free. Assume small rotations 2) (1 Assume that h 119 mm and b 112 mm Use the compatibility equations (geometry of deformation) to obtain the ratio between the change in length of rod (1) and rod (2), i.e., δ1/δ2. Find the flexibility of rod (1), which has elasticity modulus E1 164 MPa and diameter d=29 mm Find the flexibility of rod (2), which has elasticity modulus E2 198 MPa and diameter Use the results above and the constitutive relation to determine the ratio between the internal forces in rods (1) and (2), i.e., Fı/F2. Note that you are not expected to use equilibrium equations at this step F1 | F2 = By combining the relation above with equilibrium equation(s), we can obtain the internal forces F and F2 and consequently the normal stresses σ1 and σ2 in rods (1) and (2) respectively. For this step, assume the rigid beam is loaded with W 83 N MPa MPa

Answer 1

Ans:

EI 164x106 xo.o21 . 102x17) n 0