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A rigid beam ABCD is supported by a pin at B and two cables located at A and C. The cables have a 30 mm diameter and are made

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pfc P=200 KN im 2 m 1.4m FB FA Efy=0) - FA+ FB + Fc - 200 KN DO FB + FO-FA = 200 KN EMB=0; lsum of moment about B) FAXI + 2xDo Fc The best 19 X L2 fc = force in cable at a AC = cross-section area at cable c - 750mm 12 = length of cable at a BA x 15mFA+ 2x2 FA = 680 FA = 136HN Fo= 2 FA = 272 KN Fc X 22. Do = ACXE E = 200 copa 22=750mm = 272X1000 X 750 IX 30% 200x1000 1.443

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