Question

Write a program that, given a month and year, prints a calendar, such as June 2016 Su Mo Tu We Th Fr Sa 5 6 7 8 910 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 To find out the weekday of the first day of the month, call this function: Computes the weekday of a given date. @param year the year @param month the month (1=January 12= December) @param day the day of the month @return the weekday (0 Sunday... 6 Saturday) int day of week(int year, int month, int day) int y year; int m-month - 1; if (month < 3) y mm+4; return (yy/4 y/ 100 y /400 +3*m+4.(m.m/8) / 2 + day) % 7; Make a helper function to print the header and a helper function to print each row ****Need this in C++ Using only (<iostream>)***

Answer 1

#include <iostream>

#include <iomanip>

#include <cmath>

#include <cstdio>

using namespace std;

bool checkLeapYear(int year) {

if(year % 400)

return true;

if(year % 100)

return false;

if(year % 4)

return true;

return false;

}

int dayinfo(int year, int month, int day) {

int y = year;

int m = month - 1;

if( month < 3) {

y--;

m = m+4;

}

return (y + y / 4 - y / 100 + y / 400 + 3 * m + 4 - (m - m / 8) / 2 + day) % 7;

}

int getNDays(int month, int year) {

if( month == 2) {

if(checkLeapYear(year))

return 29;

else

return 28;

} else if(month == 4 || month== 6 || month == 9 || month == 11 ) {

return 30;

} else

return 31;

}

int main() {

int y, m;

cout<<"Enter month - MM: ";

cin>>m;

cout<<"Enter year - YYYY: ";

cin>>y;

int nDays = getNDays(m, y);

cout<<"Su Mo Tu We Th Fr Sa"<<endl;

for(int d = 1; d <= nDays;d++) {

int day = dayinfo(y, m, d);

if(d == 1)

for(int j = 0; j < day; j++)

cout<<" ";

cout<<setw(2)<<d<<" ";

if(day == 6) {

cout<<endl;

}

}

return 0;

}