In how many different ways can 2 candidates be selected from a group of 25 applicants?
300
560
1140
2300
Solution
n C x = n! / x!(n - x)!
n! = n(n - 1)(n - 2) .... and so on .
n = 25 and x = 2
25 C 2 = 25! / 2!(25 - 2)! = 25! / 2!(23)! = 25 * 24 / 2 * 1 = 300
300 different ways
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