Dilution A chemist must dilute 67.1 ml of 2.92 M aqueous potassium iodide (KI) solution unti...

Question

Question

Dilution A chemist must dilute 67.1 ml of 2.92 M aqueous potassium iodide (KI) solution unti the concentration falls to 2.00

Answer 1

Answer #1

Formula is

M1V1 = M2V2

2.92 M*67.1 mL = 2.00 M*V2

195.932 mL = 2.00*V2

V2 = 195.932 mL / 2.00

V2 = 97.966 mL

V2 = 98.0 mL ( correct to 3 significant digits)

V2 (volume)= 0.0980*10^3 mL

Answer 2

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