A rectangular solid of height h increases in optical density as its height increases, so the index of refraction of the solid increases with height according to:
n(y) = 1.10(4.00y + 1.00)
where y is the distance, in meters, from the origin (see diagram). A beam of light traveling in air (n = 1.00) in the x-y plane strikes the bottom of the tank at the origin, making an angle of incidence with the normal of ?1. Assume:
Euler's equations for extremum: f - y'(?f/?y') =
constant
n=c/v
t = ? ds/v = ?(1.20/c)(2y+1)?(1+y'^2)dx
which would make my functional:
f=(2y+1)?(1+y'^2)
and using the Euler equations above I have from
that:
(2y+1)(1+y'^2)^.5 - y'^2(2y+1)(1+y'^2)^-.5 = (2y+1)(1+y'^2)^-.5 =
constant
and that's where I'm stuck...
(2y+1)(1+y'^2)^-.5 = constant seems like it should be easy enough
to integrate with dy and dx somehow, but try as I might I'm totally
stumped.
A rectangular solid of height h increases in optical density as its height increases, so the...
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