Question

Part D In Example 20.8, what would the magnitude of the electric field of the dipole be at point A (see figure 20.29.a at left). Assume the two charges are separated by a distance of 1.2 cm and point A is 3.6 cm from the origin (Figure 1) N/C Submit Request Answer

Answer 1

In part D magnitude of charge q is not given so we take it as it is. Just put the value of q in coulombs and get the answere in N\C.

Separation between the charges is d = 1.2 cm = 1.2 times 10^-2 m. distance of point A from origin is r = 3.6 cm = 3.6 times 10^-2 m. we know that electric field of the dipole is E = qd/4 pi elementof_0 r^3 squareroot 3 cos^2 theta + 1 point A is in educational position of the dipole so theta = 90 degree E_A = qd/4 pi elementof r^3 squareroot 3 cos^2 90 + 1 \r\n E_A = qd/4 pi elementof r^3 Because 1/4 pi elementof_0 = 9 times 10^9 E_A = 9 times 10^9 times q times 1.2 times 10^-2/(3.6 times 10^-2)^3 E_A = 2.314 times 10^12 q N/C values of q is not given so we write it as q. Just but the values of q in coulomb and get the answer. part - B The electric field due to a point charge is spherically symmetric, where as that of a dipole is