Question

Dynamics Newtons second law equation. I am new to this and my book does an awful job of teaching this. Can someone please help.

13-17. The double inclined plane supports two blocks A and B, each having a weight of 10 lb. If the coefficient of kinetic friction between the blocks and the plane is As 0.1, determine the acceleration of each block. 60° 30° 1Prob. 13-17

Answer 1

10lb 60 A 0.1N NA 10 lb 30°

Equation of Motion: Since blocks A and B are sliding along the plane, the friction forces developed between the blocks and the plane are (F)Ak NA 0.1 NA and (FB NB0.1NB. Here, aA aB -a. Applying Eq. 13-7 to FBD(a), we have -儡) (0) NA 5.00 lb 32.2 10 Fe = max', T + 0.1(5.00)-10 sin 60° 32.2/ From FBD(b), +Fy may, NB- 10 cos 30° 32.2 (0) NB-8.660 lb Fma T 0.1(8.660) 10 sin 30- 32.2" Solving Eqs. (1) and (2) yields a 3.69 ft/s2 Ans. T = 7.013 lb