Question

1. A small mass of 150 grams is released from rest and allowed to fall from rest at an initial height of 1.50m to a final height of 1.00m. Determine the following: Ug tog _ Ktop=_ _U Eup Ugbox_ Khot Ebor 2. You will allow a meter stick to rotate about an axis through one end of the stick. Raise the stick so that it is horizontal, and release the stick from this position. Now determine the speed of the far end of the stick as it rotates through the vertical position (the lowest point in its swing). You will need to consider: How far the center of the stick falls (think about this) The moment of inertia of the stick about an end (look this up in the chapter on rotation). How do you write out rotational kinetic energy (I'll give you this one) KERot=1w2 and v = rw

Answer 1

Given data, Initial haight h zS0m nitialvelocity, uso Final height, h'e 1om Mass, m =0-15 9 Vgtop-mxgh Kitopmu Ktop 0 uo) O15x9.8X LS Ug bot mg h Etop top t Ktop 220J+0 Etop 2,20J bot - Cth Ebot = Etop ENot2.20J Kect = Eto-Bot 2120 4 Kbot o.73J