Question

TRIAL 1 600 2.610 9.91 o.2 0.39 2.62 43 Average Result: The average speed of the given ball is velas hralels 1) Pull the penduum to the side, insert the ball into the gun, and compress and latch the gun spring Release the pendulum so that it hangs vertically 2) Fire the gun. The pendulum will latch near the highest point of its swing. Measure ne height ha·the vertical distance from the pendulum platform to the center of the ball when the pendulum is latched to the side. 3) Release the pendulum so that itis vertical and measure the height hs, the distance from the pendulum platform to the center of the ball when the pendulum is vertical. Then obtain h ha-h 4) Measure the mass 'M of the pendulum, and the mass im' of the bail. Use equation (1) to calculate the speed of credit the ball v (use average of the th'values to calculate the speed of the ball), Show this work to get full 5) Repeat the measurement several times to get some error stetisticsD Conver rm 8 85 今,S Bull 9.8 lo Result: The average speed of the given ball before collision is n aory both should be equal 37 Questions 1) Compare your different trials for table A, and give a brief description of it. Are they What do you think is the most important source of random error in this part of the experiment? Compare your value for v from table B with your value from table A. Taking the table A value to be equivalent to the theoretical result (since it does not depend on any assumptions about energy and momentum), what is the percent error of your table , value? The formula is % error-(difference / theoretical ) . 100%. (Show your work.) 2) 3) Based on your answer to question 2, would you conclude that momentum and energy are conserved in this experiment? Explain. 38 LAB9 PHY 151/ PHY251 Inelastic Collision Latb Aim Name: Partner David, A In this lab we will study motion in two-dimensions. An object which has motion in both the X and y directions has a two dimensional motion. We will also study about the conservation of energy and momertum We will determine by two different means the velocity of the ball fired from the firing mechanism, and compare the results. Theony Here, we will assume that the pendulum consists of a mass of small dimensions suspended by a massless cord. Let the mass of the ball be 'm' and the mass of the pendulum be M. Let the horizontal speed of the ball before collision be vand of the pendulum plus ball nght after the collision be ν, when the ball strikes the pendulum and sticks it is a completely inelastic collision and energy is not conserved. pendulum mass and the ball. For the momentum is before the collision t Define the system as the the system horizontal momentum is conserved for a very short time from just to just after the collision as for this short period there are no horizontal forces acting on the system. When the pendulum has swung to the side a bit the cord of the pendulum exerts a horizontal force on the pendulum mass and horizontal momentum is no longer conserved. The horizontal linear momentum of the system just before the collisions is mu (M m)V. Right after the collision the pendulum mass and ball swing up against the force of gravity and eventualy come to rest. Assuming no friction, energy is conserved during this part of the motion as the force of the gravity which is conservative and the force suspending the cord do no work. Let the gravitational potential ener be zero. At this time the total energy is then kinetic and equal to % (MemV2, when the pendulum has stopped the kinetic energy is zero but the gravitational potential energy is (M-m)gh, where s the vertical distance that the pendulum mass and ball have gone up. Equating the total energies at these two times gives % (M(Mmigh. Eliminating V between these equations gives 1) Swing the pendulum out of the way so that the latching mechanism holds the pendulum to the side. nd of the gun. Obtain the vertical distance 'd' by measuring Put the ball, which has a hole in it, on the rod at the e the distance from the bottom of the ball to the floor with a meter stick. gun against the action of the spring. Push far enough so that the spring is latched. Aim the gun across a clear spot in the lab room. Being sure no one is in the way, depress the firing lever on top of the gun and observe where the ball lands on the floor. Measure this horizontal distance, rangeD where the ball first hits the floor 3) Fire the gun several times to build up some error statistics for the distance D 4) Calculate the speed of the ball v' as it leaves the gun (use average of the D values to calculate the 9.80 mis for your calculation. speed of a projectile by a kinematic method), Show this work. You must use g 36

Answer 1

Answer:

1). B). Asparagine-glycine-tyrosine

2). B). Prophase I

Explanation: Exchange of chromatid segments between non-sister chromatids of homlologous chromosomes is called crossing over. It occurs in meiosis I.

3). C). 1 pair of sex chromosomes and 22 pairs of autosomal chromosomes are pictured

Explanation:

Male = 22A + XY

Female = 22A+XX

4). D). They’re the main site of photosynthesis in autotrophs

Explanation:

Chloroplast composed of a liquid-filled space known as stroma. They are found in plant cells. They are full of flattened stacks of membranes called thylakoids.

5). C). Electron transport chain.

Explanation:

Glycolysis= 2 ATP

Kreb’s cycle = 2 ATP

Electron transport chain = 32 ATP

6). B). Store

Explanation: The main role of DNA in the cell is the long-term storage of information.

7). 7). D). The body failing to respind to signals that slow the cell cycle.

8). A). Exposing a plant to a higher light intensity

9). B). Telophase

Explanation: Nuclear envelope disappears in prophase and reappears in telophase.

10). D). Anaphase II

Explanation:

Homologous chromosomes move towards to opposite poles in meiosis I. Sister chromatids move towars opposite poles in anaphase II