Question

Procedure: Fire a practice shot. Locate the landing point on the floor then secure a piece of white paper to the floor (centered about the landing point). Cover the sheet with a piece of carbon paper and tape it down. 1. Shoot the ball at least 5 times. Take care not to disturb the position of the launcher during the shots. 2. Measure the vertical height H of the projectile launcher from the floor. (Use a plumb bob determine the true vertical distance to the floor). Record value in the Table. 3. Measure the horizontal displacement R for each trial and record values in the table. 4. Calculate the average <R> of the horizontal distance. 5. Find the initial velocity vo of the projectile using the < R > and H values. Data Table 1: Trial # Range R(m) 1 2.260 2.264 Vertical Height H = 0.925 m Absolute error in distance 4 H = AR = 0.001 m Horizontal range <R>=__2.262_(m) Time of flight t = _0.925 (sec) Initial Velocity v=-11.966 (m/s) +-0.005 2 3 2.280 4 2.254 5 2.250 <R>= 2.262 m Part II: Ballistic Pendulum Method yo Page 3 of 7

Answer 1

Part I:- Table & Average range Page <R> - 2.260+ 2.264+ 2.280 + 2-254+ 2-25 5 le = 0.925 m ( 9 9.8 Qe(a) t KRY = 2.2616 (ans) Hosizontal Ronge KR) - 2.2616 m Time of flight t: 24 Where. He is vertical theight 9.8 ms) themefase. t= (2x0.925 t = 0.189 Seconds (Ans) (a) :- Toftial velocity vo = Holzotal Range <RS Vo = 2.2616 € 0.001 0.189 Vo = 11.966+ 0.005 m/s Part II :- Total mass 3 (M = mb + mp) mb= 0.0658.6 Mp= 0.24709 M= 0.06586+0.24709 M= 0.31295 kg length of Personen met het = 0.290m h= 0.290 (l-coso) Time of flight t kg kg kg

2 192 For foail 1, 0= 35° h = 0.290 (1-C02 35") = 0.052 h = 0.0524 For troul 2, O = 36° h= 0.290(1- Cos 360) = 0.0554 h = 0.0 554 Far trail 3,4 36° h = 0.0 554 for trail 5, h = 0.0524 o therefore Average ha <h> = 0.0524 +0.0 =.0.0524 +0.0554 +0.05547 0.0 554 70.0 5 <h): 0.0542

3 5 ogle so = 11 Initial veloci Where h is are + 0.001 aug oo quenoje 0: <0) - 35136+36+36735 g- {0} = 35.6 Vanilkal displacement <h> = 0. 0542 Absolute error in velocity - v: fagh average height or ch> + absolute orror Absolvite error in Rom = Rom h = Rom (1-сoso) (35.6+11° tfence error în 1- Cos 0 = d (l- Coso) 10 do (00).sino (+1). Sin [35.6) (EXT 1 sin (35.6) o (i-Coso) = 10.01 Sh = Rom + s (1-сoso) sh= + (0.001+ 0.01) + 0.011 h = 0.0542 + 0.011 116) ſaxgxh Vax 2 x 9.8 %0.0542 U - 1.03 m/s - 180

Pg. Ab, erood in velocely. Av=g (sh Jh173 Dre! (0.011) (0.0542):\/2 Sv=0.0236 de initial velocity U= (1-03+0.0236)m/s Cans.
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