Question

(please explain your answers). for the following transfer function,

a) determine if the associated system is BIBO stable

b) if BIBO stable systems in question a). For these systems, determine the steady state output Yss(t) given

- an input u(t) = 2step(t) → Yss(t) = lim t→+∞ (y(t)) = constant value

-an input u(t) = 3 sin(t) → Yss(t) = sin function

c) if non BIBO stable systems in question a). For these systems, find a bounded input that makes the output unbounded

Answer 1

"GU (s) = 1/s pole lies of origin so it is stable system (BIBO) (when i/p is 2 ult) i/p = 2/s = y (s)/y (s) = 1/s = y (s)/2 (s) = 1/s = y (s) = s/2 s \r\n y (s) = 1/2 rightarrow Inverse Laplace y (f) = 1/2 s (f) i/p = 3 sin t w = 1 G (j w) = 1/j w L^a (j w) = -90