Question

Constants ? Part A What is the net resistance of the circuit connected to the battery in the figure (Figure 1)? Each resistance has R = 2.6k?. Express your answer using two significant figures Rnet Submit Request Answer Provide Feedback Next > 1 of1 12 V

Answer 1

Here ,

for R and R in series

R1 = R + R = 2R

R1 and R in parallel

R2 = 2R * R/(2R + R) = 2R/3

Now R2 and R in series

R3 = R + 2R/3 = 5R/3

R3 and R in parallel

R4 = (5R/3) * R/(5R/3 + R)

R4 = 0.625*R

Now R4 and R in series

Req = 0.625R + R = 1.625 * R

Req = 1.625 * 2.6 kOhm

Req = 4.22 kOhm

the net resistance is 4.22 kOhm