a)
sample mean 'x̄= | 5.900 |
sample size n= | 49.00 |
sample std deviation s= | 6.900 |
std error 'sx=s/√n= | 0.9857 |
for 95% CI; and 48 df, value of t= | 2.011 | |
margin of error E=t*std error = | 1.982 | |
lower bound=sample mean-E = | 3.918 | |
Upper bound=sample mean+E = | 7.882 | |
from above 95% confidence interval for population mean =(3.92,7.88) ; reject Ho |
b)
test stat t ='(x-μ)*√n/sx= | 5.986 |
reject Ho at all value of alpha , extremly strong evidence
c)
test stat t ='(x-μ)*√n/sx= | 2.942 |
p value = | 0.003 |
Exercise 10.16 METHODS AND APPLICATIONS Suppose a sample of 49 paired differences that have been randomly...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean of d? 5 and a sample standard deviation of sd-7. (a) Calculate a 95 percent confidence interval for μο" μι-P2. (Round your answers to 2 decimal places.) Confidence interval 2.989 7011 (b) Test the null hypothesis Ho: μ.-0 versus the alternative hypothesis Ha: Ha ? 0 by setting ? equal to 10, 05, 01, and .001....
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d⎯⎯ =4.6d¯ =4.6 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =5.0d¯ =5.0 of and a sample standard deviation of sd = 7.8. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =4.2 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ ? , ?...
Suppose a sample of 49 paired differences that have been randomly selected from a nomally distributed population of paired differences yeids a sample mean of 2t-5and a sample standand deviation of s a) Calculate a 95 percent confidence interval for pa P-Pa-(Round your answers to 2 decimal places 299。. 701 이 Cotoncerterval. [ versus the atermative hypothesis H a 7 0 by setting 7 equal to 10, 05,01, and 001. How much evidence is there that ers fom (b) Test...
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: Ho<0; a=0.01. Sample statistics: d = 1.8, Sa = 3.4, n = 13 Identify the null and alternative hypotheses. Choose the correct answer below. 0 O B. Ho Hd < 0 Ha Ha 20 OD. Ho Hd = 0 O A. Ho Hd >...
Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 70 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting µ represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to...
Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 63 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting µ represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to...
that's all the data i have. Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.01 to test for a difference between the weights of discarded paper in pounds) and weights of discarded plastic (in pounds) E Click the icon to view the data. In this example, He is the mean value of the...
Independent random samples selected from two normal populations produced the sample means and standard deviations shown to the right. a. Assuming equal variances, conduct the test Ho (H1-H2) = 0 against Hy: (H1-H2) #0 using a = 0.10. b. Find and interpret the 90% confidence interval for (H1-H2) Sample 1 Sample 2 ny - 18 ng - 11 X2 7.8 X = 5.6 Sy = 3.1 82 4.7 a. Find the test statistic, The test statistic is (Round to two...