Question

w = 0.00084 J (I can't figure out the mass of the piece of fruit correctly)

A hardworking ant must supply 0.00955 N to pull a small piece of fruit at constant velocity over a distance of 8.80 cm up a small hill to the entrance of the colony. If the coefficient of kinetic friction between the piece of fruit and the 24.2° sloped hill is 0.400, calculate the work done by the ant by pulling the piece of fruit up the hill. Number W= Use the work-energy theorem to calculate the mass of the piece of fruit in grams. (The acceleration due to gravity is 9.81 m/s2.) Number m = g

Answer 1

x F = applied force mgsins mg cosa Given, es = normal force = mass of the fruit fx & kinetic friction force 8 = 24.29 F=0.00955N My = 0.400 od - 8.80cm = 8.80x10 m = 0.088 m. 6 The work done by the ant by falling the piece of fruit up the hill is, -Exd F. d = id = 0.00955 x 0.088 = 0.00084 5 from the free body diagram, considering the vertical forces, sa mguso - considering the & Losizontal Jorces, may = f - imgsing-tx mxo = &- ing sing-te es va constar > F-ngsino - My =0
Thanks