Show the output of the following piece of code: public static void main(String[] args) { char...
Homework Answers
The output of the above code is:
b
c
-2
For understanding I have palced comments in the code which specifies what each statement does.
Output generated:
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Show the output of the following piece of code:
public static void main(String[] args)
{
char...
What output is produced by the following program? public class MysteryNums public static void main(String[] args)...
What output is produced by the following program? public class MysteryNums public static void main(String[] args) - int x = 12; int y = x - 3; 3, sentence (y, x + y); . public static void sentence (int numi, int num2) { 4: System.out.println(num1 + " + num2);
Review the following code: public class Looping { public static void main(String[] args) { ...
Review the following code: public class Looping { public static void main(String[] args) { for (int i = 1; i <= 5; i++) { for (int j = 1; j <= 5; j++) { System.out.println(i + " x " + j + " = " + (i * j)); } } } } What is the output from the code above? Replace this text with your solution What happens if you change the...
how to change this code to string instead of int public static void main(String[] args)...
how to change this code to string instead of int public static void main(String[] args) { int[] sample = { 212, 580, 6, 7, 28, 84, 112, 434}; Dictionary bst = new Dictionary(); for (int x : sample) { bst.insert(x); } System.out.println(bst.find(65)); System.out.println(bst.smallest()); System.out.println(bst.largest()); // bst.delete(84); System.out.println(bst.numOfLeafNodes()); System.out.println(bst.height()); bst.traverseInOrder(); } }
Analyze the following code: public class Test { private int t; public static void main(String[] args)...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Analyze the following code: public class Test { private int t; public static void main(String[] args)...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
1. What is the output when you run printIn()? public static void main(String[] args) { if...
1. What is the output when you run printIn()? public static void main(String[] args) { if (true) { int num = 1; if (num > 0) { num++; } } int num = 1; addOne(num); num = num - 1 System.out.println(num); } public void addOne(int num) { num = num + 1; } 2. When creating an array for primitive data types, the default values are: a. Numeric type b. Char type c. Boolean type d. String type e. Float...
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (...
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ] else if (s.charAt (i)'t') System.out.print (s.charAt (i-2)) i+ti else System. out. print (s . charAt (İ) ) ; if (i<2) System.out.print ("y"); System.out.println ()
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ]...
What will be the output of the following Java code? class Output { public static void...
What will be the output of the following Java code? class Output { public static void main(String args[]) { boolean a = true; boolean b = false; boolean c = a ^ b; System.out.println(!c); } } a) 0 b) 1 c) false d) true
Given the following Java code: public static void main (String[] args) { int num; System.out.println("Enter a...
Given the following Java code: public static void main (String[] args) { int num; System.out.println("Enter a number"); num = scan.nextInt(); <-first input statement while (num != 0) { System.out.println ("The number is: " + num); System.out.println("Enter a number"); num = scan.nextInt(); } //End While } //End Module The first input statement shown above is called the:
what is output public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int...
what is output
public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int w 0; int x; int y 5; float z = 6.1 System.out.print("Enter y: "); x keyboard.nextint); System.out.println('y'); System.out.println(x); System.out.println(w*3); x- x+(int)z; System.out.println(x); 0 System.out.println(u); System.out.,println(u); System.out.println"x In" + y); System.out.print(y + z); ) liclosing main method 1 liclosing class header
What output is produced by the following program? public class MysteryNums public static void main(String[] args) - int x = 12; int y = x - 3; 3, sentence (y, x + y); . public static void sentence (int numi, int num2) { 4: System.out.println(num1 + " + num2);
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ] else if (s.charAt (i)'t') System.out.print (s.charAt (i-2)) i+ti else System. out. print (s . charAt (İ) ) ; if (i<2) System.out.print ("y"); System.out.println ()
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ]...
what is output
public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int w 0; int x; int y 5; float z = 6.1 System.out.print("Enter y: "); x keyboard.nextint); System.out.println('y'); System.out.println(x); System.out.println(w*3); x- x+(int)z; System.out.println(x); 0 System.out.println(u); System.out.,println(u); System.out.println"x In" + y); System.out.print(y + z); ) liclosing main method 1 liclosing class header
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