how to change this code to string instead of int public static void main(String[] args)...
how to change this code to string instead of int
public static void main(String[] args) {
int[] sample = { 212, 580, 6, 7,
28, 84, 112, 434};
Dictionary bst = new
Dictionary();
for (int x : sample) {
bst.insert(x);
}
System.out.println(bst.find(65));
System.out.println(bst.smallest());
System.out.println(bst.largest());
// bst.delete(84);
System.out.println(bst.numOfLeafNodes());
System.out.println(bst.height());
bst.traverseInOrder();
}
}
Homework Answers
public static void main(String[] args) {
String[] sample = { "212", "580", "6", "7", "28", "84", "112", "434"};
Dictionary bst = new Dictionary();
for (String x : sample) {
bst.insert(x);
}
System.out.println(bst.find("65"));
System.out.println(bst.smallest());
System.out.println(bst.largest());
// bst.delete(84);
System.out.println(bst.numOfLeafNodes());
System.out.println(bst.height());
bst.traverseInOrder();
}
Add Answer to:
how to change this code to string instead of int
public static void main(String[] args)...
Analyze the following code: public class Test { private int t; public static void main(String[] args)...
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Analyze the following code: public class Test { private int t; public static void main(String[] args)...
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Review the following code: public class Looping { public static void main(String[] args) { ...
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what is output public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int...
what is output
public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int w 0; int x; int y 5; float z = 6.1 System.out.print("Enter y: "); x keyboard.nextint); System.out.println('y'); System.out.println(x); System.out.println(w*3); x- x+(int)z; System.out.println(x); 0 System.out.println(u); System.out.,println(u); System.out.println"x In" + y); System.out.print(y + z); ) liclosing main method 1 liclosing class header
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import java.util.Scanner; public class SCAN { public static void main(String[ ] args) { int x, y,...
import java.util.Scanner; public class SCAN { public static void main(String[ ] args) { int x, y, z; double average; Scanner scan = new Scanner(System.in); System.out.println("Enter an integer value"); x = scan.nextInt( ); System.out.println("Enter another integer value"); y = scan.nextInt( ); System.out.println("Enter a third integer value"); z = scan.nextInt( ); average = (x + y + z) / 3; System.out.println("The result of my calculation is " + average); } } What is output if x = 0, y = 1 and...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
what is output
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