A capacitor C is charged to an initial potential of 60.0 V, with an initial charge of Q0. It is in a circuit with a switch and an inductor with inductance L = 5.33
eenrgy in RL Ckt is given by U = 0.5 Li^2
here we need current i
so
from graph
V at 0.8 secs = 30 V
initial Volatge V = 60 V
so
use the equation V = Vo(1-e^-Rt/L)
1-e^-Rt/L = 30/60 = 0.5
e^-Rt/L = 1-0.5 = 0.5
-Rt/L = ln (0.5) = -0.693
so
R = 0.693*L/t
R = 0.693 * 0.0533/16
R = 0.0023 ohms
so
intiial current i = V/R = 60/0.0023 = 25990 A
current after 16 periods
i = io e^-RT/L
i = 25990 * e^-(0.0023 * 16/0.053)
i = 12979 Amps
so energy U = 0.5 LI^2
U = 0.5 * 0.0533 * 12979*12979
U = 4.489 *10^6 Joules
-----------------
apply part B :
e^-Rt/L = 0.93
-Rt/L = ln(0.93)
t = 0.0725 * L/R
t = 0.0725 * 0.0533/0.0023
t = 1.68 secs
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