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HW Ch 18 Thermodynamics (Heat Engines) and Ch 19 Electric Charges, Forces <HW Ch 18 Thermodynamics (Heat Engines) and Ch 19 E

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The answer for above problem is explained below.

We know that, кa, Q, Fe 2 12 And e = meg KQ, Q2 meЯ - Х- К4, 82- е Я => And take 8=y And Q, =q кa, G. kqq... 2 Чs meg me g -)

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