Electrostatic force is given by
F = k*Q1*Q2/R^2
So force that charge 1 exerts on charge 3 will be
F13 = k*q1*q3/d1^2
where, d1 = distance between q1 and q3
Now force that charge 2 exerts on charge 3 will be
F23 = k*q2*q3/d2^2
where, d2 = distance between q2 and q3
Now given that
|F13| = |F23|
k*q1*q3/d1^2 = k*q2*q3/d2^2
given that
q1 = q & q2 = 4q & q3 = q, So
k*q*q/d1^2 = k*4q*q/d2^2
(d2/d1)^2 = 4
d2/d1 = sqrt 4 = 2
d2 = 2*d1
distance between q2 and q3 = twice of distance between q1 and q3
in other words d2 > d1
Now in above given configurations only A ad C follows above relation, So
Correct Answer: AC
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