Consider the following reaction:
Cd2+ (aq) + 4CN- (aq) ↔ Cd(CN)2- (aq)
In this particular reaction CN- is acing as a
1. |
Bronsted Lowry acid |
|
2. |
Bronsted Lowry base |
|
3. |
Lewis acid |
|
4. |
Lewis base |
|
5. |
Both a and c |
|
6. |
Both b and d |
Cd2+(metal ion) have an velance orbital to accept an electron pair thus Cd2+ is a lewis acid.
But anion (CN-) have one or more unshared electro pairs to donate thus CN- is a lewis base.
Ans:4 lewis base
Consider the following reaction: Cd2+ (aq) + 4CN- (aq) ↔ Cd(CN)2- (aq) In this particular reaction...
PLEASE ONLY ANSWER FIRST QUESTION Consider the following reaction: Cd2+ (aq) + 4CN (aq) +- Cd(CN)2- (aq) In this particular reaction CN is acing as a 1. Bronsted Lowry acid 2. Bronsted Lowry base 3. Lewis acid 4. Lewis base 5. Both a and c 6. Both b and d QUESTION 5 The solubility of Zinc hydroxide, Zn(OH)2, in water when dilute nitric acid is added to it? 1. Increases 2. First decreases, then increases 3. Does not change 4....
The following Lewis acid-base reaction has A.G° =-39.9 kJ. Cd2+ (aq) + 4 NH3(aq) → [Cd(NH3)4]2+(aq) What is the formation constant of [Cd(NH3)4]2+ at 25 °C? (R = 8.314510 J/Kºmol) 1. -1.0 x 107 2. 1.0 x 107 3. 1.0 x 10-7 4. 1.3 x 1016
urgentt 5) The molecular complex Cd(CN)d-dissociates in water by the process Ca(CN)"(aq) = Cd2+(aq) +4 CN- Kc = 1.3 x 10-7 The initial concentration of Cd(CN).- in an aqueous solution is 0.0360 M. No Cd2+ or CN-ions are initially present. What is the concentration of Cd2+ ion present when equilibrium is achieved? [12 points]
Acids and bases: Part I Consider the following reactions: (a) 2 NH3 + Ag+ → [Ag(NH3)2]+ (b) NH4+ + CO32- → NH3 + HCO3- (c) 2 HBr + Ca(OH)2 → CaBr2 + 2 H2O Match with the definitions that apply for the substances indicated. Note: In a given reaction, the same definition must apply for both the acid and base for it to hold true. Choices: a)Lewis-base b)Bronsted-Lowry and Lewis Base c) Lewis acid d) Arrhenius, Bronsted-Lowry, and Lewis acid...
In each row check off the boxes that apply to the highlighted reactant. The highlighted reactant acts as a... (check all that apply) reaction Bronsted-Lowry acid Bronsted-Lowry base HNO2(aq)+C,HNH2 (0g) NO2 (aa)+ C2H,NH (aq) Lewis acid Lewis base Bronsted-Lowry acid Bronsted-Lowry base HCN(aq) + CH,NH (aq)CN (aq) + CH,NH (aq) Lewis acid Lewis base Bronsted-Lowry acid Bronsted-Lowry base 2 CH (g)+ Br()2 CH,Br(g) + H2() Lewis acid Lewis base
How can I tell which substances are donating electrons and which are accepting electrons? Identify the Lewis acid and Lewis base that lead to the formation of the following species: (a) AICI, (b) Cd(CN) (c) HCO3, (d) H SO (a) AlCl3 + Cl → AICIG AIC13 (Lewis acid), CI (Lewis base) Cd²+ (Lewis acid), CN (Lewis base) (b) Cd2+ +4CN Cd(CN) (c) H+ + což – HCO3 (d) H+ + HS04 — H2SO4 H (Lewis acid), COŽ- (Lewis base) H...
Consider the following Bronsted-Lowry Acid/Base neutralization reaction: NH3 (aq) + HBr (aq) => NH4+(aq) + Br-(aq) Please list 1.) the acid and 2.) the conjugate base in this reaction.
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E o (Fe2+ / Fe) = −0.4400 V, E o (Cd2+ / Cd) = −0.4000 V Calculate the emf for this reaction at 298 K if [Fe2+] = 0.60 M and [Cd2+] = 0.010 M. E =____ V Will the reaction occur spontaneously at these conditions? yes no cannot predict
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E° (Fe2+ / Fe) =-0.4400 V, Eº (Cd2+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe2+] = 0.85 M and [Cd2+] = 0.010 M. E= Lv Will the reaction occur spontaneously at these conditions? o o yes no cannot predict o
Consider the half‑reaction for the reduction of Cd 2+ Cd2+ to Cd(s) Cd(s) . Cd 2 +(aq)+2 e − ⟶Cd(s) ? ∘ Cd 2+ /Cd =−0.403 V Cd2+(aq)+2e−⟶Cd(s)ECd2+/Cd∘=−0.403 V Calculate the potential of the cadmium electrode at 25 ∘ C 25 ∘C when immersed in a 0.0560 M 0.0560 M solution of CdBr 2 . CdBr2. ? Cd = ECd= V V Calculate the potential of the cadmium electrode at 25 ∘ C 25 ∘C when immersed in a 0.0330...