Suppose you titrate 0.310 L of a 0.350 M solution of sodium nicotinate with 6.0 M HCl. Ka for nicotinic acid is 1.5*10-5.
What is the pH of the solution before beginning the titration?
What is the pH of the solution halfway through the titration?
What is the pH at the stoichiometric point?
What is a suitable indicator for this titration?
Suppose you titrate 0.310 L of a 0.350 M solution of sodium nicotinate with 6.0 M...
1. You are titrating a 100.0 mL solution of 0.050 M HBrwith a 0.150 M solution of KOH. What will be the pH after the addition of 25.0 mL KOH? 2. You titrate 250 mL of 0.250 M acetic acid (Ka= 1.8 x 10-5) with 50.0 mL of 0.350 M NaOH. What is the pH of this solution? 3. For the titration in question 2, what would be the Kaof an ideal indicator.
Calculate the pH in the titration of 45.0 mL of 0.350 M accetic acid by sodium hydroxide after the addition to the acid solution of 10.5 mL of 0.250 M NaOH. The ka of acetic acid is 1.8 x 10^-5
A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate. Calculate the pH of the solution following the addition of 0.066 moles of NaOH. Assume that any contribution of the NaOH to the volume of the solution is negligible. The Ka of butanoic acid is 1.52 × 10-5. A 1.44 L buffer solution consists of 0.326 M propanoic acid and 0.103 M sodium propanoate. Calculate the pH of the solution following the addition of...
You titrate 15 mL of a 0.10 M solution of methylamine (pkb = 3.36) with a titrant that is 0.10 M HCl. What is the pH at the midpoint (halfway point) of the titration? Select one or more: a. Cannot be determined from given information b.pH = 11.04 c.pH = 7.00 = d. pH = 10.64 e.pH = 3.36 You titrate a 25 ml sample of 0.10 M ammonia (Ko = 1.8 X 105) with 0.15 M HNO3. At the...
fident you decide to titrate a 0.10s L solution of Malotic ngak diprotic acid. Titrating with 045 M NaOH o e after adding 37.2 ml of NaOH Fee H-Mal for with 0.45 M NaOH you was the original concentration of Malonic acid? 1.5 x 10 for Malonic acid what was the original pH of the b IfKa 1.5x 10 for any NaOH? What is pH after adding only 18.6 mL of 0.45 M NaOH? e. d. What is in solution...
Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide. The volume of 21.70 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) the concentration of the cyanic acid solution before the titration b) the pH of the cyanic acid solution before the titration c) the pH of the solution at half-equivalence point
Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium hydroxide. The volume of 27.40 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) The concentration of the chloroacetic acid solution before the titration b) the pH of the chloroacetic acid solution before titration c) the pH of the solution at half equivalence point d) the pH of the solution at the equivalence point e) the pH of the solution when...
1. Here you have a saturated solution a. Calculate the molar solubility of cadmium (I)hy b. (extra credit) What is the pH of this solution? c. What would be the molar solubility of cadmium () () on of cadmium (ID hydroxide, Cd(OH)2 at 25 oC. (1.5 pts) sodiumn byodar solebiliy of yxide when the solution nitily contains 0.010 M of sodium hydroxide (NaOH)? d. um (lI) hydroxideicther the following chemicals can increase or decrease the solubility of cadmium (II) hydroxide....
A 1.47 L buffer solution consists of 0.329 M propanoic acid and 0.188 M sodium propanoate. Calculate the pH of the solution following the addition of 0.073 mol HCl. Assume that any contribution of the HCl to the volume of the solution is negligible. The Ka of propanoic acid is 1.34 x 10-5. pH=
A 1.37 L buffer solution consists of 0.251 M propanoic acid and 0.130 M sodium propanoate. Calculate the pH of the solution following the addition of 0.079 mol HCl. Assume that any contribution of the HCl to the volume of the solution is negligible. The Ka of propanoic acid is 1.34 x 10-5. pH = 4.86