MC CH6 #29 B & C
MC CH6 #29 B & C
Homework Answers
B) For the reaction
CH4 --> C(g) + 4H
The enthalpy of reaction = Sum of enthalpy of products- sum of enthalpy of reactants
Enthalpy of reaction = (enthalpy of C(g) + 4X enthalpy of H) - (Enthalpy of CH4)
Let us put the values from table given
Etnhalpy of reaction = (718.4 + 4 X 217.94) - (-74.8) = 1664.96 KJ / mole
C) For reverse reaction
Enthalpy of reaction = (Enthalpy of CH4) - (enthalpy of C(g) + 4X enthalpy of H)
Enthalpy of reaction = -74.8 - ( 718.4 + 4X 217.94) = -1664.96 KJ / mole
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