Question

Can you help me to complete this Lab work, table and calculation and give a conclusion...Thank you...

PHYS 204 L-Archimede's Principle: Buoyancy and Specific Gravity AIM: The aim of this laboratory exercise is to investigate the relationship between the buoyant force exerted on a submerged object and the specific gravity of that object, and to determine the specific gravity. NAME: GROUP I DATE: 01/2</20 Dimensions of samples Diameter or Width (cm) Length (cm) Height (cm) SAMPLE 2-46 4.26 4. 26 SAMPLE 2 in D. 301 10301 0.301 SAMPLE 3 Table 1 SAMPLE 1 SAMPLE 2 SAMPLE 3 24 1.0.24 kg 33 0.033 kg Volume of sample (cm) Volume of water displaced (cm) Mass of displaced water (kg) Weight of displaced water WD (N) Mass of sample in air (kg) Weight of sample in air, W (N) Mass of sample submerged in water (kg) Weight of sample submerged in water W' (N) Buoyant force Fp (N) [W-W') 0.201 kg 0.895 kg 0,165 kg 0.038kg Table 2 SAMPLE 1 SAMPLE 2 SAMPLE 3 Sample Material Known S.G. S.G. = W/WD (Archimede's principle) S.G. - W/FB % Error ANALYSIS/SAMPLE CALCULATIONS:

Answer 1

Ansever? I solve the problem SAMPLE WISE : Srbomple 1 rolume = (length x width x height) am - 6:48 x 4.26x4=26) : . 45 em! Now, weight = mass & gravity i weight of sample 18 (in water), (acceleration due to W=6.165\* 4-8) N gravity=908 95²) = 1•617 N of weight . displaced water Wo = 0.2hx 908 = 2.35 N sample in air. W =0.201 * 98 = 1097 N. weight of

Bonyant force Fo= 1097-10617= wow' = 0.353 N. Known Specific Gravity will be the - S.Go of the material taken, not given in question] Now, 18.6= w = 30.838) Sample 1 . (Acc. to Archimedes Principle) S.G=W-5.58

% age error : This will depend on the instrument . which is used to measure the mass of The Bample, I suppose the minimum amount of weight . the instrument can measure is a kg. The error in weight measurement will be: % age essor in weight = ( 2 P +100) %.

o erron in S.Gm (acc. to Archimedes Princie) o weight of displaced water is in the denominator Formula = n (least count 100% l observed value and for multiplication of two values, their errors get added up, & for dirisson, errors get subtracted

SAMPLE 2 volume = (0.30) x 0.301 x 0.301) cam? = 0.027 cm Wo= 0.033 x 908 = 0.323 1 W= 0.895 x 9,8 = 8.771 N W = 0.372 N. SiGo (Acc. to. Archimedes principle) certo - Bottes = 27.15 S.69 w .- 8.771 = 1.044 1. 8.771 -0.372.

% age errosyal hay 1 - 0 3 23.) % 087091 8.771 0.323 (If the mass of water is measured by measuring the volume of water & thus: & density (I gun ce.") = massive volume then error in mass of water: xxx minimum graduation in volumetric cylinder "volume measureda