Homework Answers
Answer:
Consider the C code statement:
C[4] = B[i+j]
Translate C code to RISC-V code as follows:
![add r0, x28, x29 lw rl, r0 (x30) sw rl,16 (x31) #r0 gets i+j value #load rl to get B[i+] value #stor e the value of B[i+j]in](http://img.homeworklib.com/questions/5c5f2a90-ca69-11ea-9236-3d3b3749f538.png?x-oss-process=image/resize,w_560)
Explanation:
- Assume r0, and r1 are the registers to hold the pointers of B and C.
- Add i+j values and store in r0 register.
- Load the r0 register represented as an index in the register r1.
- Store the value in the register at the index of each byte represent as 4bits, so 4bytes represented as16bits.
- Hence the statement represents as C[4]->4*4=>16(x31)
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