Answer:
Consider the C code statement:
C[4] = B[i+j]
Translate C code to RISC-V code as follows:
Explanation:
Problem 1 (15 points) Translate the C code below into RISC-V, knowing that the values of...
Problem 2.4: For the RISC-V assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers x5, x6, x7, x28, and x29, respectively. Assume that the base address of the arrays A and B are in registers x10 and x11, respectively. х30, х5, 3 add x30, x10, х30 // x30 %3D &A[F] slli x31, х6, 3 add x31, x11, х31 // х31 %3D &B[g] x5, 0(х30) // x30...
2.4 For the RISC-V assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers x5, x6, x7, x28, and x29, respectively. Assume that the base address of the arrays A and B are in registers x10 and x11, respectively. silix30, x5, 3 // x30=f*8 add x30, x10, x30 // x30=&A [f] s111 x31, x6 , 3 // x31 = g.8 add x31, x11, x31 // x31=&B [g]...
2.7 5<S$2.2, 2.3> Translate the following C code to RISC-V. Assume that the variables f, g, h, i, and j are assigned to registers x5, x6. x7. x28, and x29, y. Assume that the base address of the arrays A and B are in registers x10 and x11, respectively. Assume that the elements of the arrays A and B are 8-byte words: 2.7 5 Translate the following C code to RISC-V. Assume that the variables f, g, h, i, and...
1 slli x30, x5, 3 add x30, x10, x30 slli x31, x6, 3 add x31, x11, x31 ld x5, 0(x30) addi x12, x30, 8 ld x30, 0(x12) add x30, x30, x5 sd x30, 0(x31) // x30 = f*8 // x30 = &A[f] // x31 = g*8 // x31 = &B[g] // f = A[f] For the RISC-V assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers...
Please do the following problems 1. translate into RISC-V Assembly variable rpt in x19 register. if(rpt>0){ rpt=rpt-1; goto loop } 2. Translate the following Risc-V code into C. variable 'i' in register x5, variable 'result' in x6 ,base address of integer 'memarray' in x10 addi x6,x0,0 addi x29,x0,100 LOOP: ld x7,0(x10) add x5,x5,x7 addi x10,x10,8 addi x6,x6,1 blt x6,x29, LOOP
7. Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a,b, i and j are in registers Ss0, Ss1, St0, and St1, respectively. Also, assume that register SS2 holds the base address of the array D. for(i-0; i<a; i++) for(j=0 ; j<b; j++)
IN MIPS AND MUST RUN IN QTSPIM Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a, b, i and j are stored in registers Ss0, Ss1, St0 and Stl, respectively. Also assume that register Ss2 holds the base address of the array D. for (i=0; i<a; itt) for (i-0j<b:jt+)
Translate the following C code to MIPS assembly. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also assume that $s2 holds the base address of the array D. for (i = 0: i < a: i++) for (j = 0: j < b: j++) D[2 * j] = i + j;
Using beq only, not bge! Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also, assume that register $s2 holds the base address of the integer array D. Comments are required. for(i=1; i<a; i++) for(j=1; j<b; j++) D[2*j] = i + j;
please code using risc-v language and make it as simple as possible Problem 1: (20 marks) Part 1: (15 points) Compile the RISC-V assembly code for the following C code. Assume that n and k are passed in x3 and x4 respectively. Values n and k are initialized to 14 and 14. Assume that result returned in register fl and that double precision numbers are used. After you are done store the result in address: 12(x3). Are you allowed to?...