1) The correct answer is option (E).
During the anaphase stage of meiosis I and
mitosis, homologous chromosomes separate and move
towards the spindle poles so that one chromosome of homologous pair
reach to each gamete.
During the anaphase stage of meiosis II, sister chromatids
separate. Hence, option (C) is incorrect.
2) The correct answer is option (D).
Crossing over is defined as the exchange of genetic material between the homologous chromosomes of non-sister chromatids to form genetic recombinants. This occurs during the diakinesis stage of prophase I of meiosis I.
3) The correct answer is option (D).
Random fertilization, independent assortment, and genetic
recombination are the primary ways that increase the genetic
diversity.
Each gamete contains a unique set of genes. The fertilization
between a male and female occurs randomly. As a result, a zygote
receives a unique combination of genes and hence variation occurs
which leads to genetic diversity.
Genetic recombination is the exchange of genetic material between
the homologous chromosomes of non-sister chromatids to form genetic
recombinants. This allows a novel combination of maternal and
paternal genetic material and causes genetic diversity.
Independent assortment occurs during metaphase I of meiosis I.
Here, during the formation of gametes, the allele pairs (homologous
chromosomes) segregate randomly and independently of each other. It
results in the formation of gametes with unique combinations of
chromosomes which also leads to the genetic diversity.
4) The correct answer is
option (C).
Let us suppose that chocolate color is represented by a recessive
allele b and black color is represented by a dominant allele
B.
According to the question, chocolate labs are homozygous recessive.
This means that the genotype of chocolate lab is bb.
Parents: Bb X bb
Gametes: B,
b
b
Offsprings: 1 Bb : 1 bb
(Black
lab) (Chocolate lab)
If we consider option (1), all the offsprings will be Bb. Hence,
this option is incorrect.
If we consider option (2), 3 types of offsprings will produce,
i.e., BB, Bb and bb in the ratio of 1:2:1. Hence, this
option is incorrect.
If we consider option (4), 2 types of offsprings will produce,
i.e., BB and Bb in the ratio of 1:1. But as given in the
question, bb represents chocolate lab. Therefore, this option is
also incorrect.
5) The correct answer is option (d).
Both parents have the same genotype, i.e., Tt.
The cross between them follows as
Parents:
Tt
X Tt
Gametes:
T,t T,t
Offsprings:
Gametes | T | t |
T | TT (Normal offspring) |
Tt (Normal offspring) |
t | Tt (Normal offspring) |
tt |
From the Punnett square, it is clear that 1/4, i.e., 25% offsprings
are affected and produce a serious disease.
Chapters 11-12 Practice your Knowledge Activity separate daring or crossitig over C Mciosis n. D Mitosis...
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