Implement F(A,B,C)=(A+B+C)(A’+C’)(B+C’) using a 2x1 Multiplexer and using a 4x1 Multiplexer.

Question

Question

Answer 1

Answer #1

F(A,B,C)=(A+B+C)(A'+C')(B+C')

=(A+B+C)(A'+B+C')(A'+B'+C')(A+B+C')(A'+B+C')

=(A+B+C)(A'+B+C')(A'+B'+C')(A+B+C')

=(0+0+0)(1+0+1)(1+1+1)(0+0+1)

=M0 . M5 . M7 . M1

= $gif.latex?%5Cprod$ M(0,1,5,7) $gif.latex?%5CRightarrow$ max terms

F(A,B,C)= $gif.latex?%5Csum$ m(2,3,4,6) $gif.latex?%5CRightarrow$ min terms

Answer 2

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