See the example Capstone graph from the Lab Manual (Figure 3, a
velocity vs. time curve). What region of this graph represents the
time when the cart is moving down the incline?
1) From A to C
2) From B to C
3) From A to B
I am not certain how to answer this. Please help as soon as
possible? Thank you?
2nd Question:
See the example Capstone graph from the Lab Manual (Figure 3, a
velocity vs. time curve). Once you have created a graph like this,
what will you do with it?
1) Make a quadratic fit to the data (From A to C) to find the
acceleration.
2) Find the time at which the curve crosses the V=0 x-axis(point
B).
3) Make a linear fit to the data(From A to C) to find the
acceleration.
4) Make two linear fits to the data (one from A to B, and the other
from B to C), to find two accelerations.
5) Make two quadratic fits to the data(one from A to B, and the
other from B to C), to find two accelerations.
I'm stuck between 3 and 4 answers. one linear or two linears??
Please help soon as possible. Thank you.
See the example Capstone graph from the Lab Manual (Figure 3, a velocity vs. time curve)....
need help please DO A QUADRATIC FIT ON THE POSITION VS, TIME GRAPH, THE VALUE OF THE QUADRATIC "A QUAL TO HALF OF THE ACCELERATION. WHY? D A ALUINEAR FIT ON THE VELOCITY VS. TIME GRAPH. THE VALUE OF THE SLOPE IS EQUAL TO THE ACCELERATION, WHY? COMPARE THE ACCELERATION VALUES FROM BOTH GRAPHS. DO PERCENT DIFFERENCE. POST-LAB QUESTIONS: IF THE CART DID NOT ACCELERATE, WHAT WOULD BE THE SHAPES OF THE POSITION VS. TIME AND THE VELOCITY VS. TIME...
Please note that X is time Value Position vs Time Linear Fit m y = mx + b Quadratic Fit Α. B 0.305 -0.0583 y=0.305x -0.0583 4 1 0.110 -0.0663 0.195... yöllx'-0.0663x7.195 |(1.550, 0.359) 1(1.600,0.373) 0.28 y = Ax?+ Bx + C (x1, yı) (x2, Y2) Slope For Position vs Time data: (a) Did your quadratic fit of this graph provide initial position? If yes, what is its value? (4 points) (b) Did your quadratic fit of this graph provide...
For this page: The person's velocity vs. time graph is given to be: 4 Velocity (m/s) 0.50 m/s 2.0 4.0 Time (s) -0.5 m/s the position vs. time graph. Include units, labels, and numerical values on the graph. B. What is the person's average velocity? What is the person's average speed? D What is the person's instantaneous acceleration att3.0 s? , what is the person's instantaneous velocity at t = 1.0 s? PHY 201 Lab Manual
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PHY 201 Lab Mansal (Spring For this page: The person's velocity vs. time graph is given to be PHY 201 Lab Manaal (Spring 2019 version) For this page: The person moves forward slowly with a back to the initial position quickly, with a speed of 2.0 m/s speed of 1.0 m/s for 2.0s then comes 18. Sketch the position va. time graph. Include units,Ilabels, and numerical values on the graph BSketch the velocity vs. time graph. Include units, labels, and...
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