When light of wavelength 120 nm falls on a gold surface, electrons having a maximum kinetic...
When light of wavelength 120
nm falls on a gold surface, electrons having a maximum kinetic
energy of 5.25 eV are emitted. Find values for the following.
Homework Answers
A photon of 120 nm will have
E = hc/lamda
E = 1249/120 = 10.4 eV
Work funtion = Energy - K max
W F = 10.4 - 5.25 = 5.15 eV
Cutoff wavelength = hc/WF = 1249 /5.15 = 242.5 nm
Frequncy = c/wavelgnth = 1.23 1015 Hz
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