Question

Use the node-voltage method to find vo in the following circuit. 4Ω 2 H 4cos(4t) A 62 F. A. vo (t) 7.67 cos(4t- 35.020) V Using the mesh-current analysis to obtain Io in the following circuit 2202A 2Ω j2Ω 12 FA. 1°-3.35<174.3° A

Answer 1

Z_c = 1/j w_c Z_L = j wL where w = 4 rad/sec (given) Apply nodal at node - A v_0 - 32 angle -90 degree/94 - 3j) + v_0 - 0/(6 + 8j) + v_0 - 0/1 = 4 angle 0 degree v_0 [1/4 - 3j + 1/(6 + 8j) + 1] = 4 angle 0 degree + 32 angle -90 degree/(4 - 3j) v_0 [(6 + 8j) + 4 - 3j + (4 - 3j) (6 + 8j)/(4 - 3j) (6 + 8j)] = 4 (4 - 3j) + 32 (-j)/(4 - 3j) \r\n v_0 [10 + 5j + [24 + 32j - 18j + 24]/(6 + 8j] = 16 - 12j - 32j/1 v_0 = (16 - 44j) (6 + j8)/(24 + 24 + 10 + 5j + 32j - 18j volt v_0 = 16 times 6 + j8 times 16 - j44 times 6 + 44 times 8/(58 + 19j) volt v_0 =
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