Question

A massless spring with k = 118 N/m is hung from a support and a 1.48 kg mass is attached to the bottom of the spring. The position of the mass when it is in equilibrium is y = 0. If the mass is displaced below this point, we take its displacement to be positive. At t = 0, the mass has the initial conditions  y(0) = 0.2 m and [dy/dt]_t=0 = −1.3 m/s.

Its position at later times is
y(t) = A cos(ωt + δ) .

A massless spring with k = 118 N/m is hung from a support and a 1.48 kg mass is attached to the bottom of the spring. The position of the mass when it is in equilibrium is y = 0. If the mass is displaced below this point, we take its displacement to be positive. At t = 0, the mass has the initial conditions y(0) = 0.2 m and (dy/dt]= = -1.3 m/s. Its position at later times is y(t) = A cos(wt+d). 12. [1pt] What is the value of A? Answer: Submit All Answers 13. [1pt] What is the value of w? Answer: Submit All Answers 14. [1pt] What is the value of d? Answer: Submit All Answers

Answer 1

solution : ok We have y (6) = A cos Cast &8) y (O) = A cos (8) = 0.2m du - Aco sin (w t+8) :-)13 mis of Then Awl sin 8) = 1,3 —> 0 w = Vkim (4.88 8.93 rolles? 34 A COS S -0-2 -> >A (8.932 sin s=1.3 from 0 and (': from eqo). de Tan 8 = 1. 3 6.2) (8.93) S = 36.05°com) 0.6292 radi 1-Answer . for (C) * Then A cos 8 = 0.2 Az 0:3|co(26.057 >>70-248m) Ansioner for * value of w is a = 8.93 rad) see Answer for